I have a folder named'sample' and it contains three files I want to write a shell script which will read these files inside the sample folder and post them using curl in an http site
I wrote the following for the listing of the files inside the folder
for dir in sample/*; do echo $dir; done
But the following result comes to me
sample/log sample/clk sample/demo
It is attaching the parent folder in it. I want the output as follows (without the parent folder name)
log clk demo
How should you do it?
basename to strip the leading path off of the files.
for file in sample/*; do echo "$(basename "$file")" done
But why not?
( cd sample; ls )