Find the php version on the windows command line
I just tried to know version of my PHP from windows command typing,
C:\> php -v
But it is not working. It says php is not recognized as internal or external command.
In command prompt type below
set PATH=%PATH%;C:\path\to\php
Where C:\path\to\php is the folder where your php.exe file is located. After this run
C:\>php -v
than you will see something like
PHP 7.3.6 (cli) (built: May 29 2019 12:11:00)
UPDATE:
When you restart your computer this solution will not work anymore
Set the path as follows
Step 1 - Click on the
Windowsicon
Step 2 - Click on the
Settingsicon
Step 3 - Click on
System
Step 4 - Click on
About
Step 5 - Click on
System info
Step 6 - Click on
Advanced system settings
Step 7 - Click on
Environment variables...
Step 8 - Select
Pathrow and then clickEdit
Step 9 - Click
Newand then clickBrowse, then in the next panel which will open you need to select the folder you want in thePath. For the initial premise of this guide i will add the folderC:\Users\NewFolderInPath♥Note : Replace your PHP installed path(e.g:
C:\Program Files\php) with the above path ♥.
Step 10 - Click
OKand click everyOKbutton you will encounter to close every previous windows.









