What should i do to get the path of the main class of a java program?

structure is


I want to get the path as D:\Project\bin\ .

I tried System.getProperty("java.class.path"); but the problem is, if I run like

java -classpath D:\Project\bin;D:\Project\src\  Main

Getting : D:\Project\bin;D:\Project\src\
Want    : D:\Project\bin

Is there any way to achieve this?

===== EDIT =====

Got the solution here

Solution 1 (By Jon Skeet)

package foo;

public class Test
    public static void main(String[] args)
        ClassLoader loader = Test.class.getClassLoader();

This was printed out


Solution 2 (By Erickson)

URL main = Main.class.getResource("Main.class");
if (!"file".equalsIgnoreCase(main.getProtocol()))
  throw new IllegalStateException("Main class is not stored in a file.");
File path = new File(main.getPath());

Note that most class files are assembled into JAR files so this won't work in every case (hence the IllegalStateException ). However, you can locate the JAR that contains the class with this technique, and you can get the content of the class file by substituting a call to getResourceAsStream() in place of getResource() , and that will work whether the class is on the file system or in a JAR.

Best Answer



see http://docs.oracle.com/javase/tutorial/essential/environment/sysprop.html

You can also split it into it's elements easily

String classpath = System.getProperty("java.class.path");
String[] classpathEntries = classpath.split(File.pathSeparator);